Promotion of Government servants through Limited Departmental Competitive Examination against whom disciplinary / criminal prosecution are pending: Department of Posts dated 22.09.2023

No. X-7/6/2022-SPN-II
Government of India
Ministry of Communications
Department of Posts

Dak Bhawan, Sansad Marg
New Delhi 110 001
September 22, 2023

To,
a) All Chief Postmasters General,
b) Chief General Manager, PLI/ Parcel / BD Directorate
c) Director RAKNPA/ Director of all Postal Training Centres
d) Add. Director General, Army Postal Service
e) All General Manager (Finance) / Director of Accounts (Postal)

Subject: Promotion of Government servants through Limited Departmental Competitive Examination against whom disciplinary / criminal prosecution are pending reg.

Madam/Sir,

I am directed to refer to Directorate letters of even number dated 17.05.2023 on the above mentioned subject and to convey approval of the Competent Authority for following modification / clarification:-

A. Para 4(g)(ii) of letter of even number dated 17.05.2023 shall be modified as under:-

‘Where this penalty is imposed before applying for LDCE:- Even during the currency period of the penalty, Government servant shall be allowed to apply for appearing in LDCE if otherwise eligible. Both eligibility and currency period of penalty will be examined w.r.t. the crucial date of eligibility. By the time of declaration of results, if the penalty is not modified to any other form of penalty or exoneration, results shall not be declared. However, Covering Note (write up) of LDCE Results should clearly mention- ‘Results of … (name of the employee) … has not been declared as he/she is not eligible for promotion because of the penalty imposed vide Order No ….. dated ….. If the penalty is modified to any other form of penalty or exonerated, action shall be taken with reference to such modified decision.

B. In Para-4 (b), (d), (e) & (f) of letter of even number dated 17.05.2023, for the clause “although the official has been declared successful, promotion will be effective after (date to be specified) because of the penalty imposed vide Order No…..dated…….”, following shall be substituted:-

‘although the official has been declared successful, promotion will be effective after currency of the penalty imposed vide Order No…..dated…….

C. While declaring marks, there is no need of mentioning anything relating to penalty in case of candidates not coming in merit list as they would not be given any promotion. However, if at a later date such a candidate is proposed to be declared as successful for giving promotion, effect of penalty if any shall invariably be mentioned.

Yours faithfully,

Sd/-
(Satya Narayana Dash)
Director (SPN)

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F.11054/2/2017/KVS(H)/RPS

Dated: 16.04.2018

NOTICE

Kendriya Vidyalaya Sangathan has conducted the written Examination for the post of Lower Division Clerk from 19th February, 2018 to 23rd February, 2018 in various shifts. In preperation of result of written examination for the post of LDC, Score Normalization Method has been adopted by KVS. The formula of Score Normalization Method is placed below.

sd/-
(TAJUDDIN SHAIK)
Assistant Commissioner (RPS)

Score Normalization

About Normalization
Normalization means adjusting values measured on different scales to a notionally common scale.

Need for Normalization in Exam
Exam pertaining for a particular post/course could be spread across multiple shifts which will have different question paper for each shift. Hence the normalization of scores need to be carried out for all the candidates who had written the exam, across shifts for the same post/course.

Normally, after the exam, candidates are provided a window of few days, post the publishing of question paper and the correct keys. Based on the objections raised, SMEs work on that and with customer consultation finalize to ignore some objected questions and the remaining questions will be considered for score evaluation and subsequently the score normalization.

Inputs required for score normalization process
1. Raw score report of the candidates who appeared for a particular post, across all shifts.
2. The actual number of valid questions to be considered, post the objection

Score Normalization logic
The following has to be calculated across all shifts for all the candidates who have written the exam for the same post.

Total Number of Questions (A)
Defined as the number of questions available in the question paper. (e.g. 120 questions)

As an example, ASSUME the question papers has 120 questions

Total Number of Correct Questions (B)
Defined as the number of valid questions which have to be considered for score evaluation and score normalization, post the finalization of questions after the candidates have raised objections (if any)

B = A – # questions which are removed post candidate objections

ASSUME there are 3 invalid questions in (A)

Then B = 120-3 = 117

Example: ASSUME a candidate has attempted 103 out of 117 questions, of which 98 are correct responses and 5 are wrong resonses. 14 un-attempted questions will be Blanks.

Total Correct Responses (C)
Defined as the number of responses which are answered correctly by the candidate for the total number of valid questions (B)

In the example C = 98
Candidate Score (D)
Total Correct responses (D)

In the example D = 98

Candidate Score to be considered for Normalization (E)
Consider the case where scores will be based on 120. So, score (D) of every candidate is to be prorated i.e. it has to be multiplied by the factor: 120/B

In the example E = (D/B)*100 = (98/117)*120 = 120 = 100.5128205

Now we need to calculate Average and Standard Deviation for each Shift

Calculation of Standard Deviation Example : 9 candidates attended a shift

Xav is the average which is total marks divided by no. of candidates

Xav = : L /No. of candidates present for that particular shift = 585 / 9 = 65

Standard Deviation = square root of ∑x²/N = square root of 4356/9 = square root of 484 = 22

Total Raw Scores for all candidates in a shift (L)
Sum of Raw candidates raw scores (X) for all candidates in a shift

L = ∑X

In the SD example L = 585

Simple Average (Xav)

Total Raw score for all candidates in a shift (L) / Total candidate (Present) count for a shift
= L /N

Standared Deviation (S)
Calculated at a shift level bases on the candidate’s scores

To be calculated as explained in the example

Normalized Score for each candidate (Xn)

Xn = (S2/S1) * (X-Xav) + Yav

Criteria for choosing the base for normalization is generally taken as the shift with ‘Highest Average’ of raw scores. Only exception is made if this shift (with highest average) has far less number of candidates as compared to other shifts. In that case we take the next shift with ‘highest Average’ as base for normalization.

70% of the average attendance is the limit. Any value below this should not be considered for the base. (This percentage can be set to any value)

Source: http://kvsangathan.nic.in

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